(x^2)/(3)-(x+3)/(4)=(19)/3

Solution for (x^2)/(3)-(x+3)/(4)=(19)/3 equation:

x in (-oo:+oo)

(x^2)/3-((x+3)/4) = 19/3 // - 19/3

(x^2)/3-((x+3)/4)-(19/3) = 0

(x^2)/3-((x+3)/4)-19/3 = 0

(-1*(x+3))/4+(x^2)/3-19/3 = 0

(-1*3*(x+3))/(3*4)+(4*x^2)/(3*4)+(-19*4)/(3*4) = 0

4*x^2-1*3*(x+3)-19*4 = 0

4*x^2-3*x-76-9 = 0

4*x^2-3*x-85 = 0

4*x^2-3*x-85 = 0

4*x^2-3*x-85 = 0

DELTA = (-3)^2-(-85*4*4)

DELTA = 1369

DELTA > 0

x = (1369^(1/2)+3)/(2*4) or x = (3-1369^(1/2))/(2*4)

x = 5 or x = -17/4

(x+17/4)*(x-5) = 0

((x+17/4)*(x-5))/(3*4) = 0

((x+17/4)*(x-5))/(3*4) = 0 // * 3*4

(x+17/4)*(x-5) = 0

( x+17/4 )

x+17/4 = 0 // - 17/4

x = -17/4

( x-5 )

x-5 = 0 // + 5

x = 5

x in { -17/4, 5 }